Let's say that 64% the people on an island are get a rash when they touch a poisonous plant. studies have shown that these people must have at least one copy of a particular dominant allele. what percentage of the population must be heterozygous for this trait if this population conforms to hardy-weinberg expectations for this gene?

Question

Holly Farmer

Mathematics

1 December, 16:58

Let's say that 64% the people on an island are get a rash when they touch a poisonous plant. studies have shown that these people must have at least one copy of a particular dominant allele. what percentage of the population must be heterozygous for this trait if this population conforms to hardy-weinberg expectations for this gene?

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Answers (1)

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Haiden Wood · Answer 1

We are given with

p2 + 2pq = 0.64

and another formula is

p2 + 2pq + q2 = 1

Substituting

0.64 + q2 = 1

q2 = 1 - 0.64

q2 = 0.36

q = 0.6

Another formula is

p + q = 1

p = 1 - 0.6

p = 0.4

What is asked is 2pq

p2 + 2pq = 0.64

2pq = 0.64 - 0.4^2

2pq = 0.48

There is 48% that has the heterozygous trait.