14 August, 10:14
How to solve 45 45 90 triangle given hypotenuse?
14 August, 10:28
From the Special Triangle Theorem, the hypotenuse is equal to the side lengtht times the Sqrt (2).
So hypotenuse H = xSqrt (2), x=H/Sqrt (2).
Using numbers, if H = 7, then x = 7/Sqrt (2) = 7Sqrt (2) / 2 to rationalize it.
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