Given that, in a certain school, the following are true, what is the probability that a student is taking math or computer science?

1. The probability that a student is taking math is 33%.

2. The probability that a student is taking computer science is 62%.

3. The probability that a student is taking math and computer science is 58%.

The probability that a student is taking math or computer science is 0.37

Step-by-step explanation:

The probability that a student is taking math = P (M) = 33% = 0.33

The probability that a student is taking computer science = P (C) = 62%=0.62

The probability that a student is taking math and computer science = P (M∩C) = 58%=0.58

So, the probability that a student is taking math or computer science i. e. P (M∪C)

So, Formula:P (A∪B) = P (A) + P (B) - P (A∩B)

P (M∪C) = P (M) + P (C) - P (M∩C)

P (M∪C) = 0.33+0.62-0.58

P (M∪C) = 0.37

Hence the probability that a student is taking math or computer science is 0.37