How do you " find, to the nearest tenth of an inch, the diagonal of a square whose perimeter is 28 inches?"

Question

Fred

Mathematics

10 June, 02:13

How do you " find, to the nearest tenth of an inch, the diagonal of a square whose perimeter is 28 inches?"

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Answers (1)

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Rylan Hall · Answer 1

Well if the perimeter is 28 inches, each side of the square is 7 inches. 28/4 = 7 because all sides of a square are the same.

If we split the square in half to create 2 triangles we can find the length of the diagonal. The two sides are the bases of 7 inches.

Use the Pythagorean theorem to solve for the hypotenuse or the diagonal.

7^2 + 7^2 = diagonal ^ 2

Therefore, the diagonal equals 9.9 inches.