A park in a subdivision is triangular-shaped. Two adjacent sides of the park are 573 feet and 536 feet. The angle between the sides is 58 degrees. To the nearest unit, find the area of the park in square yards.

A) 32,557 yd2

B) 14,470 yd2

C) 28,940 yd2

D) 43,410 yd2

Question

Pirate

Mathematics

12 October, 02:33

A park in a subdivision is triangular-shaped. Two adjacent sides of the park are 573 feet and 536 feet. The angle between the sides is 58 degrees. To the nearest unit, find the area of the park in square yards.

A) 32,557 yd2

B) 14,470 yd2

C) 28,940 yd2

D) 43,410 yd2

+5

Answers (1)

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Flint · Answer 1

First, we convert the lengths of the sides from feet to yards:

573 ft = 191 yd

536 ft = 178.7 yd

Area of a triangle is given by:

1/2 absin (C)

A = 1/2 x 191 x 178.7 x sin (58)

A = 14,473 sq yd

The answer is B.

A park in a subdivision is triangular-shaped. Two adjacent sides of the park are 573 feet and 536 feet. The angle between the sides is 58 degrees. To the nearest unit, find the area of the park in square yards.A) 32,557 yd2B) 14,470 yd2C) 28,940 yd2D) 43,410 yd2

A park in a subdivision is triangular-shaped. Two adjacent sides of the park are 573 feet and 536 feet. The angle between the sides is 58 degrees. To the nearest unit, find the area of the park in square yards.

A) 32,557 yd2

B) 14,470 yd2

C) 28,940 yd2

D) 43,410 yd2