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23 April, 13:23

How many solutions does the system of equations have Y = 4x+3 and 2Y-8x = 3

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  1. 23 April, 13:46
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    The system has no solution.

    Step-by-step explanation:

    Write the system as

    y - 4x = 3

    2y - 8x = 3

    The 2nd equation can be written as

    2 (y - 4x)

    and the system would be

    y - 4x = 3

    2 (y - 4x) = 3

    Now, call y - 4x = z. Then we would have the system

    z = 3

    2z = 3

    But if z = 3 then 2z = 6 and we have a contradiction.

    We conclude that the system has no solution.
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