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What is the correct inverse function for f (x) = e2x?

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  1. 2 May, 23:48
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    To solve this problem you must appy the proccedure shown below:

    1. You have the following function given in the problem above:

    f (x) = e^2x

    2. You can rewrite is:

    y=e^2x

    3. Interchange the variables, as below:

    x=e^2y

    3. The inverse of an exponential function is the logarithm function. Thereforem you have:

    ln (x) = ln (e^2y)

    ln (x) = 2y

    4. Then, you have:

    y=ln (x) / 2

    Therefore, the answer is:

    f^-1 (x) = ln (x) / 2
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