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29 January, 12:36

The sum of consecutive integers 1,2,3, ..., n is given by the formula 1/2n (n+1). How many consecutive integers, starting with 1, must be added to get the sum of 1081

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  1. 29 January, 12:47
    0
    1/2 * n * (n+1) = 1081

    distribute

    1/2 n^2 + 1/2n - 1081=0

    factor out 1/2

    1/2 (n^2 + n - 2162) = 0

    multiply each side by 2

    (n^2 + n - 2162) = 0

    factor

    (n-46) (n+47) = 0

    n=46, n=-47

    n cannot be negative

    n=46

    Answer 46
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