Ask Question
21 February, 13:59

Which equation represents the general form a circle with a center at (-2, - 3) and a diameter of 8 units?

x2 + y2 + 4x + 6y - 51 = 0

x² + y² - 4x - 6y - 51 = 0

x2 + y2 + 4x + 6y - 3 = 0

x2 + y2 - 4x - 6y - 3 = 0

+2
Answers (1)
  1. 21 February, 14:21
    0
    Equation for a circle of radius r with center at (h, k) is given by

    (x - h) ^2 + (y-k) ^2 = r^2

    (x - (-2)) ^2 + (y - (-3)) ^2 = 4^2

    x^2 + 4x + 4 + y^2 + 6y + 9 = 16

    x^2 + 4x + y^2 + 6y - 3 = 0

    Rearranging, the answer is

    x^2 + y^2 + 4x + 6y - 3 = 0
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Which equation represents the general form a circle with a center at (-2, - 3) and a diameter of 8 units? x2 + y2 + 4x + 6y - 51 = 0 x² + ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers