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3 February, 10:12

Am I right?

A basketball is dropped from an original height of 9 feet and on each bounce, bounces up 2/3 the distance it fell. How far will it have traveled by the time it hits the ground the 4th time?

I got 21.66667 by plugging it into the partial sum formula.

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  1. 3 February, 10:33
    0
    I think ... on first hit it will bounce 9*2/3=6 ft ... gain bounce 6*2/3 = 4 ft ... third time ... 4*2/3=8/3 ... and final ... 8/3*2/3=16/9 ... means 1.6 ft appropriate
  2. 3 February, 10:33
    0
    1st drop:

    drops: 9 feet

    bounces back up: 6 feet

    2nd drop:

    drops: 6 feet

    bounces: 4 feet

    3rd drop:

    drops: 4 feet

    bounces: 2.66666feet

    4th drop:

    drops 2.6666

    9+6+6+4+4+2.6666+2.6666=31.3 recurring
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