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19 September, 18:20

Find the area of the part of the plane 3x + 2y + z = 6 that lies in the first octant.

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  1. 19 September, 18:47
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    I solved for z and made my parameters x = u y = v z=6 - 3u-2v. So I got the integral down do root (14) double integral 1.
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