A certain computer loses half of its value every 2 years. how many years would the computer be worth 12.5 of its intial value

12.5% is equal to. 125.

Using the formula:

A = P (1/2) ^ (t/h)

Where A is the amount, P is the original, t is the time in years, and h is the half-life.

.125P = (1/2) ^ (t/2)

.125 = (√2) ^t

ln (.125) = ln (√2) * t

t = ln (.125) / ln (√2)

t = 6 years