Put the following statements into order to prove that if 3n+4 is even then n is even. Put N next to the 3 statements that should not be used. 1. Then, 3n+4=3 (2k+1) + 4=6k+7=2 (3k+3) + 1.2. By definition of odd, there exists integer k such that n=2k+1.3. Thus, if n is odd then 3n+4 is odd or by contradiction, if 3n+4 is even then n is even,.4. Therefore, by definition of odd, 3n+4 is odd. 5. Since k is an integer, t = 3k+3 is also an integer. 6. Thus, there exists an integer t such that 3n+4=2t+1.7. Suppose n is odd. 8. Thus, if n is odd then 3n+4 is odd or by contraposition, if 3n+4 is even then n is even,.9. Suppose 3n+4 is even. 10. By definition of odd, n=2k+1.

Question

Wayne Doyle

Mathematics

12 February, 01:49

Put the following statements into order to prove that if 3n+4 is even then n is even. Put N next to the 3 statements that should not be used. 1. Then, 3n+4=3 (2k+1) + 4=6k+7=2 (3k+3) + 1.2. By definition of odd, there exists integer k such that n=2k+1.3. Thus, if n is odd then 3n+4 is odd or by contradiction, if 3n+4 is even then n is even,.4. Therefore, by definition of odd, 3n+4 is odd. 5. Since k is an integer, t = 3k+3 is also an integer. 6. Thus, there exists an integer t such that 3n+4=2t+1.7. Suppose n is odd. 8. Thus, if n is odd then 3n+4 is odd or by contraposition, if 3n+4 is even then n is even,.9. Suppose 3n+4 is even. 10. By definition of odd, n=2k+1.

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Lesly · Answer 1

Answer: 7, 2, 1, 5, 6, 4, 8

Step-by-step explanation:

1. Then, 3n+4=3 (2k+1) + 4=6k+7=2 (3k+3) + 1.

2. By definition of odd, there exists integer k such that n=2k+1.

N 3. Thus, if n is odd then 3n+4 is odd or by contradiction, if 3n+4 is even then n is even,.

4. Therefore, by definition of odd, 3n+4 is odd.

5. Since k is an integer, t = 3k+3 is also an integer.

6. Thus, there exists an integer t such that 3n+4=2t+1.

7. Suppose n is odd.

8. Thus, if n is odd then 3n+4 is odd or by contraposition, if 3n+4 is even then n is even,.

N 9. Suppose 3n+4 is even.

N 10. By definition of odd, n=2k+1.

Right order:

7. Suppose n is odd.

2. By definition of odd, there exists integer k such that n = 2k+1.

1. Then, 3n+4 = 3 (2k+1) + 4 = 6k+7 = 2 (3k+3) + 1.

5. Since k is an integer, t = 3k+3 is also an integer.

6. Thus, there exists an integer t such that 3n+4 = 2t+1.

4. Therefore, by definition of odd, 3n+4 is odd.

8. Thus, if n is odd then 3n+4 is odd or by contraposition, if 3n+4 is even then n is even.