The units pf the digits of a two digits numeral is 8 if the digits are reversed the new number is 18 greater than the oringal number fund the oringal numeral

complete question:

The sum of the digits of a two-digit numeral is 8. If the digits are reversed, the new number is 18 greater than the original number. How do you find the original numeral?

Answer:

The original number is 10a + b = 10 * 3 + 5 = 35

Step-by-step explanation:

Let

the number = ab

a occupies the tens place while b occupies the unit place. Therefore,

10a + b

The sum of the digits of two-digits numeral

a + b = 8 ... (i)

If the digits are reversed. The reverse digit will be 10b + a. The new number is 18 greater than the original number.

Therefore,

10b + a = 18 + 10a + b

10b - b + a - 10a = 18

9b - 9a = 18

divide both sides by 9

b - a = 2 ... (ii)

a + b = 8 ... (i)

b - a = 2 ... (ii)

b = 2 + a from equation (ii)

Insert the value of b in equation (i)

a + (2 + a) = 8

2a + 2 = 8

2a = 6

a = 6/2

a = 3

Insert the value of a in equation (ii)

b - 3 = 2

b = 2 + 3

b = 5

The original number is 10a + b = 10 * 3 + 5 = 35