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24 December, 12:06

2x (3x+5) + 3 (3x+5) = ax^2+bf+c in the equation above a, b, and c are constants. If the equation is true for all values of x what is the value of b

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  1. 24 December, 12:25
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    2x (3x + 5) + 3 (3x + 5) = ax² + bf + c

    2x. 3x + 2x. 5 + 3.3x + 3.5 = ax² + bf + c

    6x² + 10x + 9x + 15 = ax² + bf + c

    6x² + 19x + 15 = ax² + bf + c

    6x² = ax²

    6 = a

    19x = bf

    15 = c

    As the question says, b is constant, so he can't be a variable, so he only can be 19 and f be x

    19x = bf

    19 = b

    x = f
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