A ditch contains 10 centimeters of water. Rainwater accumulates in the ditch as follows: 10 centimeters of water by the end of the 1st second, 15 centimeters by the end of the 2nd second, 20 centimeters by the end of the 3rd second, and so on. Assuming that the ditch has sufficient capacity for storage, how many centimeters of water will it have after 10 seconds?

Question

Chad Russo

Mathematics

27 November, 03:51

A ditch contains 10 centimeters of water. Rainwater accumulates in the ditch as follows: 10 centimeters of water by the end of the 1st second, 15 centimeters by the end of the 2nd second, 20 centimeters by the end of the 3rd second, and so on. Assuming that the ditch has sufficient capacity for storage, how many centimeters of water will it have after 10 seconds?

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Answers (1)

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Alicia Sloan · Answer 1

Firstly, let's create a function of f (t) where t represents the time that has past, and f (t) represents the amount of rainwater. We know that when t=1, then f (t) = 10, and t=2 then f (t) = 15. So, let's take that and analyze it:

(1,10)

(2,15)

m = (15-10) / (2-1) = 5

y-intercept = 5

∴ f (t) = 5t+5

Now we just evaluate t for 10:

f (10) = (5*10) + 5

f (10) = 55