The perimeter of a rectangle is 56 meters. if the width were doubled and the length were increased by 8 then the perimeter would be 82. What are the dimensions

Question

Rodney Villa

Mathematics

10 August, 07:55

The perimeter of a rectangle is 56 meters. if the width were doubled and the length were increased by 8 then the perimeter would be 82. What are the dimensions

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Answers (1)

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Nathaniel Gibbs · Answer 1

length l=23; width w = 5

Step-by-step explanation:

56=2*w+2*l

82=2 * (2*w) + 2 * (l+8) = 4*w+2*l+16

equation 2 - equation 1 = 82-56 = 2*w + 16 = 26

2*w=26-16=10

w=5

56-2*w=2*l

56-10=46=2*l then l = 46/2 = 23