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14 November, 22:18

It is known that x=7 is a root of the equation ax^2 + bx + 2 = 0, where a<0. Solve the inequality ax²4 + bx^2 + 2>0.

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  1. 14 November, 22:27
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    2 / (7a) < x < 7

    Step-by-step explanation:

    The product of roots of ax² + bx + c is c/a. In this case, that means the second root of the equation is ...

    ... 2 / (7a)

    Since a < 0, the parabola opens downward and 2 / (7a) < 0. The quadratic function will be positive between the two roots, on the interval ...

    ... 2 / (7a) < x < 7
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