Find the derivative of f (x) = (x^2+1) ^3 (x^2+2) ^6 using chain rule.

Question

Amore

Mathematics

5 December, 04:18

Find the derivative of f (x) = (x^2+1) ^3 (x^2+2) ^6 using chain rule.

+1

Answers (1)

Know the Answer?

Bennett King · Answer 1

Hello:

note : ((u (x)) ^n) ' = n (u (x)) ^n-1 * (u (x)) '

f (x) = (x^2+1) ^3 (x^2+2) ^6

the derivative is : f" (x) = ((x^2+1) ^3) ' (x^2+2) ^6 + (x^2+1) ^3 ((x^2+2) ^6) '

f' (x) = 3*2x (x^2+1) ² (x^2+2) ^6 + (x^2+1) ^3 (6*2x) (x^2+2) ^5