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1 August, 14:38

There are 3 consecutive positive integers. the product of the first and third integer is 6 more than 6 times the second integer. what is the smallest integer? answer

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  1. 1 August, 15:06
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    Let the three integers be x - 1 x and x + 1

    (x - 1) (x + 1) = 6x + 6

    x^2 - 1 = 6x + 6

    x^2 - 6x - 7 = 0

    (x - 7) (x + 1) = 0

    x - 7 = 0

    x = 7

    x + 1 = 0

    x = - 1

    the solutions are (7,0) and (-1,0)
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