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16 December, 19:29

If sin A = 11/61 find tan A, Cos A and Sec A

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  1. 16 December, 19:44
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    Answer:tanA=11/60 cosA=60/61 secA=61/60

    Step-by-step explanation:

    From Pythagoras rule (adjacent) = √ (61^2-11^2)

    Adjacent=√ (3721-121)

    Adjacent=√ (3600) adjacent=60

    Opposite=11 hypotenuse=61 adjacent=60

    TanA=11/60 cosA=60/61 secA=61/60
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