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Skye
Mathematics
13 April, 02:10
5sin²α+3cos²α / 3sin²α-5cos²α =
if tgα=√2
+1
Answers (
1
)
Ashton Collier
13 April, 02:28
0
Tgα = tan (α) = sqrt (2) / 1 = opposite / adjacent
opposite = sqrt (2)
adjacent = 1
hypotenuse = sqrt (opposite^2 + adjacent^2)
= sqrt (sqrt (2) ^2 + 1^2) = sqrt (3)
sin (α) = opposite/hypotenuse
= sqrt (2) / sqrt (3)
cos (α) = adjacent/hypotenuse
= 1/sqrt (3)
now we can calculate the value of
5sin²α+3cos²α / 3sin²α-5cos²α
... do the math
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