Max mixes a 14-pound bag of gravy treat dog food with a 10-pound bag of hungry chops dog food. Then max puts the mixture into small bags that each weigh 1 1/2 pounds. If the proportional relationship between the quantities of the two dog foods remain constant, how many pounds of gravy dog treat would each small bag contain?

Question

Stanley

Mathematics

10 August, 15:13

Max mixes a 14-pound bag of gravy treat dog food with a 10-pound bag of hungry chops dog food. Then max puts the mixture into small bags that each weigh 1 1/2 pounds. If the proportional relationship between the quantities of the two dog foods remain constant, how many pounds of gravy dog treat would each small bag contain?

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Answers (1)

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Andrew Dean · Answer 1

7/8 pounds of gravy dog treat

Step-by-step explanation:

The total amount of food in the bag would be sum of both weights. So the total amount is 24 pounds.

The proportion of the gravy dog treat is the weight of the bag divided by the total weight, so we get 14/24 or 7/12.

Since each bag weights 1 1/2 pounds, you just have to multiply the weight by the proportion

1 1/2 * 7/12

3/2 * 7/12

21/24

7/8

So there would be 7/8 pounds of gravy dog treat.