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15 October, 17:26

Use the substitution method to solve these simultaneous equations.

a) 3x + 2y = 33

y = 41 - 5x

b) y = 3x - 3

-5x + 3y = 3

c) 4x + y = 9

y = 11 - 5x

d) x = - 5 - 2y

5y + x = - 11

e) y = 2x + 1

-5x - 4y = 35

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Answers (2)
  1. 15 October, 17:38
    0
    as

    Step-by-step explanation:

    nswer:

    Step-by-step explanation:

    a) 3x+2 (41-5x) = 33 as y=41-5x is given

    3x+82-10x=33

    -7x+82=33

    -7x=33-82

    -7x=-49 cut the negative signs as its LHS and RHS

    x=49/7=7

    b) - 5x+3 (3x-3) = 3 as y=3x-3 is given

    -5x+9x-9=3

    4x-9=3

    4x=3+9

    x=12/4=3

    c) 4x+11-5x=9

    -x+11=9

    -x=9-11

    -x=-2 cut the negative signs as its LHS and RHS

    x=2

    d) 5y + - 5-2y=-11 as x=-5-2y is given

    3y+-5=-11

    3y=-11+5

    3y=-6

    y=-6/3=-2

    e) - 5x-4 (2x+1) = 35 as y=2x+1

    -5x-8x+4=35

    3x+4=35

    3x=35-4

    3x=31

    x=31/3

    x=10.3
  2. 15 October, 17:48
    0
    Step-by-step explanation:

    a) 3x+2 (41-5x) = 33 as y=41-5x is given

    3x+82-10x=33

    -7x+82=33

    -7x=33-82

    -7x=-49 cut the negative signs as its LHS and RHS

    x=49/7=7

    b) - 5x+3 (3x-3) = 3 as y=3x-3 is given

    -5x+9x-9=3

    4x-9=3

    4x=3+9

    x=12/4=3

    c) 4x+11-5x=9

    -x+11=9

    -x=9-11

    -x=-2 cut the negative signs as its LHS and RHS

    x=2

    d) 5y + - 5-2y=-11 as x=-5-2y is given

    3y+-5=-11

    3y=-11+5

    3y=-6

    y=-6/3=-2

    e) - 5x-4 (2x+1) = 35 as y=2x+1

    -5x-8x+4=35

    3x+4=35

    3x=35-4

    3x=31

    x=31/3

    x=10.3
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