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26 February, 01:25

Let a = x^2 plus 4. Use a to find the solutions for the following equation: (x^2 plus. 4) ^2 plus 32 = 12x^2 plus 48 which of the following are solutions for x

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  1. 26 February, 01:53
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    0 or + -2

    Step-by-step explanation:

    (x^2 + 4) ^2 + 32 = 12x^2 + 48

    => x^4 + 8x^2 + 16 + 32 - 12x^2 - 48 = 0

    => x^4 - 4x^2 = 0

    => x^2 (x^2 - 4) = 0

    => x^2 = 0 or 4

    => x = 0 or + -2
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