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31 January, 05:43

AB = 44 + 3x BC = 33 + x CD = 64 - x AD = 48 - 2x Quadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruent. Prove that quadrilateral ABCD is a parallelogram by finding the lengths (in centimeters) of the opposite side pairs?

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  1. 31 January, 05:44
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    Given : AB = 44 + 3x

    BC = 33 + x

    CD = 64 - x

    AD = 48 - 2x.

    Opposite sides are AB and CD.

    BC and AD.

    Setting AB equals CD

    We get

    44 + 3x = 64 - x

    Adding x on both sides, we get

    44 + 3x+x = 64 - x+x

    44 + 4x = 64.

    Subtracting 44 from both sides, we get

    44-44 + 4x = 64 - 44.

    4x = 20

    Dividing both sides by 4, we get

    x = 5.

    Let us plug x=5 to find the length of each side, we get

    AB = 44 + 3x = 44 + 3 (5) = 44 + 15 = 59 cm

    BC = 33 + x = 33 + 5 = 38 cm

    CD = 64 - x = 64 - 5 = 59 cm

    AD = 48 - 2x = 48 - 2 (5) = 48 - 10 = 38 cm.

    We can see that AB = CD = 59 cm and BC = AD = 38 cm. Therefore, quadrilateral ABCD is a parallelogram.
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