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15 April, 21:09

If ƒ (x) = x 2 + 1 and g (x) = 3x + 1, find [ƒ (4) ] 2.

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  1. 15 April, 21:37
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    I think the function of f (x) is X^2 + 1 and I think you're looking for (f (4)) ^2. Assuming this, you plug 4 into the f function so 4^2 + 1 = 17 and 17^2 is 289.
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