Ask Question
17 October, 10:18

How much greater is the area of a square with a side length of 9 inches than the area of a circle with a radius of 3 inches?

+5
Answers (1)
  1. 17 October, 10:30
    0
    The area of the square is 81 sq in, and the area of the circule is (3.14) (3 in) ^2, or approx 3.14 (9) sq in, or approx 28.27 sq in.

    Subtract: 81 sq in - 28.27 sq in = approx. 52.73 sq in.

    The difference is 52.73 sq in; the square is larger, the circle smaller.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “How much greater is the area of a square with a side length of 9 inches than the area of a circle with a radius of 3 inches? ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers