Three consecutive integers have a sum of 135. find the integers.

Let the smallest number be x.

The other 2 numbers are x + 1 and x + 2.

Their sum is 135.

⇒ x + (x + 1) + (x + 2) = 135

Solve for x:

x + (x + 1) + (x + 2) = 135

Remove brackets:

x + x + 1 + x + 2 = 135

Combine like terms:

3x + 3 = 135

Subtract 3 from both sides:

3x = 132

Divide both sides by 3:

x = 44

Find the numbers:

Smallest number = x = 44

Middle number = x + 1 = 44 + 1 = 45

Last number = x + 2 = 44 + 2 = 46

Answer: The numbers are 44, 45 and 46