Abdul drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 7 hours. When Abdul drove home, there was no traffic and the trip only took 4 hours. If his average rate was 27 miles per hour faster on the trip home, how far away does Abdul live from the mountains?

Question

Myles Lyons

Mathematics

8 November, 02:42

Abdul drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 7 hours. When Abdul drove home, there was no traffic and the trip only took 4 hours. If his average rate was 27 miles per hour faster on the trip home, how far away does Abdul live from the mountains?

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Answers (1)

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Mila Hubbard · Answer 1

So let's call the rate abdul went on the 7 hour trip, x. Then we can say he went x + 27 on the 4 hour trip. We can then say that time times rate equals distance and make 7*x = d and 4 * (x+27) = d as valid equations, where d is our total distance. We can set the equations equal to get 4x + 108 = 7x, so x = 36. Then we can plug that into the first equation to get the total distance d = 7 (36) = 252 miles.