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27 October, 21:18

Solve systems of equations

-x^2-4x+y=0

-x^2+9x+y+13=0

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Answers (1)
  1. 27 October, 21:35
    0
    I solve it by substitution

    y=x^2+4x

    -x^2+9x + (x^2+4x) + 13=0

    13x+13=0

    13x=-13

    x = - 13/13

    x = - 1

    y=x^2+4x=1-4

    y = - 3
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