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28 December, 17:26

Using the quadratic formula to solve 5x = 6x2 - 3, what are the values of x?

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  1. 28 December, 17:47
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    6x2 - 5x - 3 = 0

    a = 6 b=-5 and c=-3

    x = [-b + - sq root (b² - 4ac) ] / 2a

    x = [--5 + - sq root (25 - 4*6*-3) ] / 2*6

    x = [5 + - sq root (25 + 72) ] / 12

    x = [5 + - sq root (97) ] / 12

    x1 = [5 + 9.8488578018 ] / 12

    x1 = 14.8488578018 / 12

    x1 = 1.2374048168

    x2 = [5 - 9.8488578018 ] / 12

    x2 = - 4.8488578018 / 12

    x2 = - 0.4040714835
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