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Today, 19:52

Supposed the population of deer in a region was 3,500 in the year 2000. since then population has grown by 3.5% annually. What will the approximate population be in the year 2020? Y=a•b^x where a is the starting amount, b is the growth rate (increasing add to 1), and x is time.

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  1. Today, 20:04
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    Y = a (b^x)

    1) x = 0, y = 3500

    => 3500 = a (b^0)

    => 3500 = a (1)

    => a = 3500

    2) growth percent = 3.5% = > growth rate = 1.035 = b

    => y = 3500 (1.035) ^ x

    3) year 2020 = > x = 2020 - 2000 = 20

    4) y = 3500 (1.035) ^ 20 = 6964

    Answer: 6964.
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