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A shipment of 20 similar laptop computers to a retail outlet contains 3 that are defective. If a school makes a random purchase of 2 of these computers, find the probability mass function for the number of defectives.

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  1. 6 May, 03:02
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    Step-by-step explanation:

    Total number of laptops, N = 20

    Defective laptops, n = 3

    School purchase 2 laptops

    Case 1:

    Both laptops are non defective

    Probability to choose 2 laptops which are non defective

    Number of non defective laptops = 20 - 3 = 17

    Total number of laptops = 20

    Probability, P = 17/20 = 0.85

    Case 2:

    One laptop is defective

    Probability to chose 1 defective and one non defective laptop

    P' = 3/20 x 17/19 = 0.134

    Case 3:

    Both laptops are defective

    Choosing of 2 laptops out of 3 = 3 C 2 = 3

    choosing of 2 laptops out of 20 = 20 C 2 = 190

    Probability of choosing two defective laptops = 3 / 190 = 0.0158

    P'' =
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