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16 May, 14:22

The inverse of the function f (x) = sin (4⋅x+3) is f-1 (x) =

(a) csc 4⋅ (x+3)

(b) arcsin 4⋅ (x+3)

(c) arcsin (x-3) / 4

(d) arcsin ((x) - 3) / 4

(e) arcsin (x-3) / 4

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Answers (1)
  1. 16 May, 14:51
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    Y = sin (4x + 3)

    4x + 3 = arcsin y

    4x = arcsin y - 3

    x = (arcsin y - 3) / 4

    Inverse = > f^-1 (x) = (arcsin (x) - 3) / 4
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