Consider this system of equations. Which equation represents the first equation written in slope-intercept form?

5X-2Y=10

Y=1/4X+1

A. Y=5/2X-5

B. Y=5/2X+10

C. Y=-5/2X+10

D. Y=-5X-5

Question

Pierce Lawrence

Mathematics

7 April, 14:14

Consider this system of equations. Which equation represents the first equation written in slope-intercept form?

5X-2Y=10

Y=1/4X+1

A. Y=5/2X-5

B. Y=5/2X+10

C. Y=-5/2X+10

D. Y=-5X-5

+4

Answers (2)

Know the Answer?

Jamar Woodard · Answer 1

Answer: A. 5/2 X - 5

Step-by-step explanation:

5x - 2y = 10

To write the equation in a slope intercept we have to make y subject of the formular

5x - 2y = 10

we will take 2y to the right-handside and 10 to the left-handside

5x-10 = 2y

2y = 5x - 10

we divide bothside by 2

2y/2 = 5x/2 - 10/2

y = 5/2 X - 10

Julia Sandoval · Answer 2

A. Y = 5/2x - 5.

Step-by-step explanation:

5X - 2Y = 10

-2Y = - 5X + 10

Divide both sides by - 2:

Y = 5/2x - 5.

Consider this system of equations. Which equation represents the first equation written in slope-intercept form?5X-2Y=10Y=1/4X+1A. Y=5/2X-5B. Y=5/2X+10C. Y=-5/2X+10D. Y=-5X-5

Consider this system of equations. Which equation represents the first equation written in slope-intercept form?

5X-2Y=10

Y=1/4X+1

A. Y=5/2X-5

B. Y=5/2X+10

C. Y=-5/2X+10

D. Y=-5X-5