A chemist is mixing one solution that is 32% sodium and another solution that is 12% sodium how many liters of each type should the chemist use to produce 50 l of the solution that is 20% sodium

In order to solve the amount of each solution, we need to set up equations. We do as follows:

Let x = solution with 32% sodium

y = solution with 12% sodium

Overall balance

x + y = 50

Component balance

.32x +.12y = 50 (.20) = 10

Solving simultaneously,

x = 20

y = 30

Hope this answers the question. Have a nice day.