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Kamari
Mathematics
5 April, 00:05
Which system is equivalent to y = - 2x, y = x-2?
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Mckinley Ortega
5 April, 00:28
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The given system of equation can be solved if x = 2/3 and y = - 4/3.
So we need to find another system which can be solved by these values.
From the given 4 options lets find out which can be solved by x = 3/2 and y = - 4/3
1.
y = - 2y^2 - 2, x = y - 2
lets put the value of y here
y = - 2 (16/9) - 2 = - 32/9-2 = - 50 / 9
So not an equivalent equation.
2.
y = - 2y^2 + 2, x = y + 2
y = - 2 (16/9) + 2=-32/9+2=-14/9
So not an equivalent system.
3.
y = - 2y^2 - 8y - 8, x = y + 2
y = - 2 (16/9) - 8 (-4/3) - 8 = - 32/9+32/3-8=64/9-8=-8/9
So not an equivalent system.
4.
y = - 2y^2 + 8y - 8, x = y - 2
y = - 2 (16/9) + 8 (-4/3) - 8=-32/9-32/3-8=-128/9-8=-22.22
So this is not an equivalent equation too
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