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Malaki Nelson
Mathematics
30 January, 01:07
Step by step how to factor:
2y^2+9y+9=0
+2
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1
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Kaliyah Kaufman
30 January, 01:23
0
Use ac method
for ax²+bx+c=0 when a≠1
multiply a and c, let's call the product r
what 2 numbesr multiply to get r and add to get b
2y²+9y+9=0
2*9=18
wat 2 numbers multiply to get 18 and add to get 9
3 and 6
split it up to that
2y²+3y+6y+9=0
group
(2y²+3y) + (6y+9) = 0
factor
y (2y+3) + 3 (2y+3) = 0
undistribute
(y+3) (2y+3) = 0
set to zero
y+3=0
y=-3
2y+3=0
2y=-3
y=-3/2
y=-3 and - 3/2
it's factored form is (x+3) (2x+3)
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