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17 June, 08:49

Find an equation of the circle having the given center and radius.

Center ( - 1, 1), radius 7

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Answers (2)
  1. 17 June, 08:53
    0
    (x+1) ^2 + (y-1) ^2=49

    Step-by-step explanation:

    The standard equation of a circle is

    (x-h) ^2 + (y-k) ^2=r^2

    where the center is (h, k) and r is the radius

    so h=-1 and k=1 in this case

    so then (x - - 1) ^2 + (y-1) ^2=7^2

    (x+1) ^2 + (y-1) ^2=49
  2. 17 June, 09:07
    0
    (x+1) ^2 + (y+1) ^2 = 49

    Step-by-step explanation:

    We can write the equation of a circle as

    (x-h) ^2 + (y-k) ^2 = r^2

    where (h, k) is the center and r is the radius

    (x - - 1) ^2 + (y - - 1) ^2 = 7^2

    Simplifying

    (x+1) ^2 + (y+1) ^2 = 49
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