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15 September, 22:49

A normal population has mean = μ9 and standard deviation = σ5. (a) What proportion of the population is less than 20? (b) What is the probability that a randomly chosen value will be greater than 6? Round the answers to four decimal places.

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  1. 15 September, 23:11
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    Step-by-step explanation:

    We would apply the formula for normal distribution which is expressed as

    z = (x - µ) / σ

    Where

    x = randomly chosen values.

    µ = mean

    σ = standard deviation

    From the information given,

    µ = 9

    σ = 5

    1) The proportion of the population that is less than 20 is expressed as

    P (x < 20)

    For x = 20

    z = (20 - 9) / 5 = 2.2

    Looking at the normal distribution table, the probability corresponding to the z score is 0.986

    P (x < 20) = 0.986

    2) The probability that a randomly chosen value will be greater than 6 is expressed as

    P (x > 6) = 1 - P (x ≤ 6)

    For x = 6

    z = (6 - 9) / 5 = - 0.6

    Looking at the normal distribution table, the probability corresponding to the z score is 0.27

    P (x > 6) = 1 - 0.27 = 0.73
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