F' (x) = 2x-3. P (-3,3)

y = x2 - 3x + 15

Step-by-step explanation:

F' (x) = dy:dx

=2x - 3

On integrating this function we get the function f (x)

y = (2 x 2: 2) - 3x + c

= x2 - 3x + c

x - 3 and y = 3

So 3 = (-3) * (-3) - 3 * (-3) + c

3 = 9 + 9 + c

3 = 18 + c

C = 15

Therefore the equation is

y = x2 - 3x + 15