A tennis club has 8 tennis ball launchers to use for lessons. Each launcher holds 27 tennis balls. If a can of tennis balls contains 3 balls, how many cans of tennis balls will be needed to fill 3/4 of the launchers one time?

54 cans

Step-by-step explanation:

8 Tennis ball launchers.

Each hold 27 balls.

One can = 3 balls.

We have 27 * 8 total balls which is equivalent to 216.

We want to find 3/4 of the total which is 216 * 0.75.

This is then = to 162

Since one can holds 3 balls.

162/3 = 54 cans.

Therefore, to fill the total of 3/4 of launchers within a lesson, 54 cans of tennis balls will be needed.

Number of cans is 6.75

Step-by-step explanation:

According to the question,

One launcher holds 27 tennis balls

3/4 launcher hold y tennis balls

Cross multiply

Y = 3/4*27

Y = 81/4

Y = 20.25 tennis balls

To determine the number of cans

One can holds 3 tennis balls

Z can holds 20.25 tennis balls

Cross multiply

3z = 20.25

Z = 20.25/3

Z=6.75 cans