What are the possible values of x in 32x + 20 = 28x - 16x2?

2x + 20 = - 16 x2 + 28x Step 2: Subtract - 16x^2+28x from both sides. 2x + 20 - ( - 16 x2 + 28x) = - 16 x2 + 28x - ( - 16 x2 + 28x) 16 x2 - 26x + 20 = 0 Step 3: Use quadratic formula with a=16, b=-26, c=20. x = - b ± √ b2 - 4a c 2a x = - (-26) ± √ (-26) 2 - 4 (16) (20) 2 (16) x = 26± √ - 604 32

4x2+x+5=0

(2x+1/4) ^2=-79/16

2x+1/4 = (√79/4) i or 2x+1/4 = - (√79/4) i

x = (√79/8) i - 1/8 or - (√79/8) i - 1/8