Show that one zero of 8x2-30x+27 is the square of the other

To show that the zero of the function is the square of the other, we factorize as follows:

8x^2-30x+27

factoring the above we get:

8x^2-12x-18x+27

factoring we obtain:

4x (2x-3) - 9 (2x-3)

= (2x-3) (4x-9)

from above roots we see that:

the zeros are:

x=3/2 and x=9/4

the second zero is the square of the first