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18 January, 18:53

Use the given data to find the minimum sample size required to estimate a population proportion or percentage. margin of error: 0.040.04 ; confidence level 9595 %; modifyingabove p with caretp and modifyingabove q with caretq unknown

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  1. 18 January, 18:59
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    Minimum required sample size for a desired margin of error and confidence level when it is a proportion problem: n = (z2:margin of error2) * p-hat*q-hat

    The maximum value of p-hat*q-hat occurs where p-hat =.5 (found by taking the derivative of (p-hat) * (1-p-hat) and setting it equal to 0 to find the maximum. n = (2.5762 (for 99% confidence interval) :.0482) *.5*.5 = 720.028 or 721
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