Which exponential function has an initial value of 2? f (x) = 2 (3x) orf (x) = 3 (2x) or neither

Question

Deshawn Buck

Mathematics

28 March, 22:14

Which exponential function has an initial value of 2? f (x) = 2 (3x) orf (x) = 3 (2x) or neither

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Answers (2)

Know the Answer?

Alissa Carey · Answer 1

The correct answer is A, C cannot be correct because f (x) = 3 (2ˣ) would be in the parenthesis. For A, f (x) = 2 (3ˣ) it's in the right spot since it's asking for the exponential function.

Walter Strong · Answer 2

F (x) = 3 (2x) is the answer in e2020, because the funciton has a value of 2 and 2+1 = 3 so that gives you 3 (2x)