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14 September, 12:25

Find the largest positive integer that will divide 398,436 and 542 leaving remainders 7,11 and 15 respectively

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  1. 14 September, 12:36
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    The greatest common divisor of (398 - 7), (436 - 11), and (542 - 15) is 17.

    398 mod 17 = 7 436 mod 17 = 11 542 mod 17 = 15

    The integer you're looking for is 17.
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