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16 August, 17:31

Use the chain rule to find dz/dt calculator

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  1. 16 August, 17:59
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    We need to find:

    z' (t) = dz (t) dt=ddt (e-3t· (-sin (2t)) 2) =

    z' (t) = dz (t) dt=ddt (e-3t· (-sin? (2t)) 2) =

    ddt (e-3tsin2 (2t)) = e-3tsin (2t) (4cos (2t) - 3sin (2t))

    ddt (e-3tsin2? (2t)) = e-3tsin? (2t) (4cos? (2t) - 3sin? (2t))

    Using:

    The product rule:

    ddt (f (t) ·y (t)) = f (t) ·ddt (y (t)) + y (t) ·ddt (f (t)) = y (t) ·f' (t) + f (t) ·y' (t) ddt (f (t) ·y (t)) = f (t) ·ddt (y (t)) + y (t) ·ddt (f (t)) = y (t) ·f' (t) + f (t) ·y' (t) ddt (ex (t)) = ex (t) ·ddt (x (t)) = x' (t) ·ex (t)

    ddt (ex (t)) = ex (t) ·ddt (x (t)) = x' (t) ·ex (t)

    When CC is a constant:

    ddt (C·q (t)) = C·ddt (q (t)) = C·q' (t)

    ddt (C·q (t)) = C·ddt (q (t)) = C·q' (t)

    When nn is a constant, using the chain rule:

    ddt (w (t) n) = n·w (t) n-1·ddt (w (t)) = n·w (t) n-1·w' (t)

    ddt (w (t) n) = n·w (t) n-1·ddt (w (t)) = n·w (t) n-1·w' (t)

    When mm is a constant, using the chain rule: ddt (v (mt)) = ddt (mt) ·v' (mt) = m·v' (mt)
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