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28 January, 07:40

Find two numbers whose square increased by 15 equals 8 times the number.

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  1. 28 January, 07:45
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    Answer:5 and 3

    So we let the number take the letter b, anc the expression of the question is:

    b^2+15=8*b ... so

    b^2+15=8b

    Then we take the 8b to the other side of the equal sign so that it becomes ...

    b^2+15-8b=0

    Hence it becomes a quadatic equation following the principle ax^2+bx+c where x is the unknown ...

    From there we work out to get two different numbers ... either b-5=0

    b=5

    Or b-3=0

    b=3

    So the two numbers are 5 and 3
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